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The probability distribution of customers that walk into a coffee shop on any given day of the week is described by a Normal distribution with mean equal to 100 and standard deviation equal to 20. What is the probability that no more than 80 customers walk into the coffee shop next Monday

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Answer:

15.87% probability that no more than 80 customers walk into the coffee shop next Monday

Explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:


\mu = 100, \sigma = 20

What is the probability that no more than 80 customers walk into the coffee shop next Monday?

This is the pvalue of Z when X = 80. So


Z = (X - \mu)/(\sigma)


Z = (80 - 100)/(20)


Z = -1


Z = -1 has a pvalue of 0.1587.

So there is a 15.87% probability that no more than 80 customers walk into the coffee shop next Monday

User MisterNeutron
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