Question

Someone help please

Answer 1

`\sf 4x+3y=12`

Explanation:

Choose two points on the line:

Let
`\sf (x_1,y_1)=(0,4)`

Let
`\sf (x_2,y_2)=(3,0)`

Use the slope formula to find the slope of the line:

`\sf slope(m)=(y_2-y_1)/(x_2-x_1)=(0-4)/(3-0)=-\frac43`

Use the point-slope formula to find the equation of the line:

`\sf y-y_1=m(x-x_1)`

Substitute values into the formula:

`\sf y-4=-\frac43(x-0)`

Expand the brackets:

`\sf y-4=-\frac43x`

Add 4 to both sides:

`\sf y=-\frac43x+4`

Rearrange into the form
`ax+by=c`

Multiply both sides by 3

`\sf 3y=-4x+12`

Add 4x to both sides:

`\sf 4x+3y=12`

Answer 2

Steps to finding the line in the diagram with the format 'ax + by = c

1. Find the slope

• To find the slope, we need any two points on the line --> (0,4) and (3,0)

`Slope = (y2-y1)/(x2-x1) =(4-0)/(0-3) =-(4)/(3)`

2. Set up, with any one point on the line and the slope, in point-slope form

`(y-y0)=m(x-x0)\\(y-4)=-(4)/(3) (x-0)\\y-4 = -(4)/(3) x\\(4)/(3)x+y = 4`

Answer:
`(4)/(3)x+y = 4`

Hope that helps!