Answer:
Concentration of stock solution in g/L = 5.0g/L
Concentration of stock solution in mol/L = 0.00117 mol/L or 0.00117 M
Step-by-step explanation:
Concentration in mol/L = (Concentration in g/L)/(Molar mass)
Mass of (NH₄)₃Fe(ox)₃.3H₂O stock = 125mg = 0.125g
Volume of stock solution required = 25mL = 0.025 L
Concentration in g/L = 0.125/0.025 = 5.0 g/L
Molar Mass of (NH₄)₃Fe(ox)₃.3H₂O = (NH₄)₃Fe(C₂O₄)₃.3H₂O = 428.0632 g/mol
Concentration in mol/L = 5/428.0632 = 0.00117 mol/L = 0.00117 M
Hope this helps!!!