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A syringe containing 1.64 mL of oxygen gas is cooled from 94.6 ∘C to 0.3 ∘C. What is the final volume Vf of oxygen gas?

User Ed Pike
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1 Answer

3 votes

Answer:


V_f=V_2=1.22* 10^(-3) L=1.22mL

Step-by-step explanation:

Use Charles's law which states: "At constant pressure, the volume occupied by a gas sample is directly proportional to the absolute temperatures they support."

This law can be expressed mathematically as follows:


(V_1)/(T_1)=(V_2)/(T_2)

Where:


V_1=Initial\hspace{3}volume=1.64mL=1.64* 10^(-3) L\\V_2=Final\hspace{3}volume\\T_1=Initial\hspace{3}temperature=94.6$^(\circ)$C=367.75K\\T_2=Final\hspace{3}temperature=0.3$^(\circ)$C=273.45K

Solving for
V_2


V_2=(V_1*T_2)/(T_1) =((1.64* 10^(-3) )*273.45)/(367.75) =1.21946431* 10^(-3) \approx1.22* 10^(-3) L =1.22mL

User Coulix
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