Someone help please

Question

asked Feb 28, 2023 170k views

2 Answers

Yavanosta · Answer 1 · 2023-03-03T02:19:37+0000

Answer:

$\sf 4x+3y=12$

Explanation:

Choose two points on the line:

Let
$\sf (x_1,y_1)=(0,4)$

Let
$\sf (x_2,y_2)=(3,0)$

Use the slope formula to find the slope of the line:

$\sf slope(m)=(y_2-y_1)/(x_2-x_1)=(0-4)/(3-0)=-\frac43$

Use the point-slope formula to find the equation of the line:

$\sf y-y_1=m(x-x_1)$

Substitute values into the formula:

$\sf y-4=-\frac43(x-0)$

Expand the brackets:

$\sf y-4=-\frac43x$

Add 4 to both sides:

$\sf y=-\frac43x+4$

Rearrange into the form
ax+by=c

Multiply both sides by 3

$\sf 3y=-4x+12$

Add 4x to both sides:

$\sf 4x+3y=12$

Imagist · Answer 2 · 2023-03-05T23:30:17+0000

Steps to finding the line in the diagram with the format 'ax + by = c

1. Find the slope

Slope = (y2-y1)/(x2-x1) =(4-0)/(0-3) =-(4)/(3)

2. Set up, with any one point on the line and the slope, in point-slope form

$(y-y0)=m(x-x0)\\(y-4)=-(4)/(3) (x-0)\\y-4 = -(4)/(3) x\\(4)/(3)x+y = 4$

Answer:
(4)/(3)x+y = 4

Hope that helps!