Question

Radium-228 decays by alpha decay. Part of the nuclear equation is shown

below. Fill in the blank with a number.
Ra → He+7 Rn
Answer here
SUBMIT

Answer 1

₈₈ Ra²²⁸ → ₂He⁴ + ₈₆Rn²²⁴

Step-by-step explanation:

Radium -228 is a radio-active element. It undergoes ∝- decay which means it emits a helium particle that is composed of 2 neutrons and 2 protons. Then the radium- 228 is converted into radon-224 which is again a radio-active element contains 86 protons and 138 neutrons by emitting an ∝-particle. The other isotopes of Ra²²³, Ra²²⁴ and Ra²²⁶ occurs naturally in the chain decay of the radio-active elements Uranium and Thorium. The ∝- decay of ₈₈ Ra²²⁸ is given as,

₈₈ Ra²²⁸ → ₂He⁴ + ₈₆Rn²²⁴

Answer 2

₈₈ Ra²²⁸ → ₂He⁴ + ₈₆Rn²²⁴

Explanation:

Radium -228 is a radio-active element. It undergoes ∝- decay which means it emits a helium particle that is composed of 2 neutrons and 2 protons. Then the radium- 228 is converted into radon-224 which is again a radio-active element contains 86 protons and 138 neutrons by emitting an ∝-particle. The other isotopes of Ra²²³, Ra²²⁴ and Ra²²⁶ occurs naturally in the chain decay of the radio-active elements Uranium and Thorium. The ∝- decay of ₈₈ Ra²²⁸ is given as,

₈₈ Ra²²⁸ → ₂He⁴ + ₈₆Rn²²⁴