Question

How many moles of sebacoyl chloride do you have if you measure out 5 mL of a 9% volume/volume solution in cyclohexane?

Answer 1

moles sebacoyl chloride = 2.1 x 10-3 mol

Step-by-step explanation:

• Concentration sebacoyl chloride = 9% (v/v) = 9 mL sebacoyl chloride / 100 mL solution
• Volume of solution measured = 5 mL
• volume of sebacoyl chloride = (Volume of solution measured) * (Concentration sebacoyl chloride)
• volume of sebacoyl chloride = (5 mL) * (9 mL sebacoyl chloride / 100 mL solution)
• volume of sebacoyl chloride = (5 * 9) / 100 mL
• volume of sebacoyl chloride = 0.45 mL
• mass sebacoyl chloride = (volume of sebacoyl chloride) * (density of sebacoyl chloride)
• mass sebacoyl chloride = (0.45 mL) * (1.121 g/mL)
• mass sebacoyl chloride = 0.50445 g
• moles sebacoyl chloride = (mass sebacoyl chloride) / (molar mass sebacoyl chloride)
• moles sebacoyl chloride = (0.50445 g) / (239.14 g/mol)
• moles sebacoyl chloride = 2.1 x 10-3 mol