Answer:
5° F
Explanation:
According to Newton's law of cooling, the rate of change is proportional to the difference between the temperature and the ambient temperature.
dT/dt = k (T − T₀)
Solving this by separating the variables:
dT / (T − T₀) = k dt
ln (T − T₀) = kt + C
T − T₀ = Ce^(kt)
T = T₀ + Ce^(kt)
We're given that T₀ = 65.
T = 65 + Ce^(kt)
At t = 10, T = 35.
35 = 65 + Ce^(10k)
-30 = Ce^(10k)
At t = 20, T = 50.
50 = 65 + Ce^(20k)
-15 = Ce^(20k)
Squaring the first equation:
900 = C² e^(20k)
Dividing by the second equation:
-60 = C
Therefore:
T = 65 − 60e^(kt)
At t = 0:
T = 65 − 60e^(0)
T = 5
The initial temperature is 5° F.