Answer:
-48cm
Step-by-step explanation:
the following data are given
focal length of telescope=200cm,
focal length of the eyepiece=0.25cm
From the genera formula used to find the magnifying power which is expressed as
![M=-(fx_(o))/(f_(e))[1+(f_(e))/(d)]](https://img.qammunity.org/2021/formulas/physics/college/oyw6o3ajzuvr6l1l7mv10i9j5eum2obqm2.png)
where

and d=least distance of distinct vision=25cm
if we substitute values into the formula, we arrive at
![M=-(fx_(o))/(f_(e))[1+(f_(e))/(d)]\\M=-(200cm)/(0.25cm)[1+(0.25cm)/(25cm)]\\M=-800cm[1+0.01]\\M=-800cm(1.01)\\M=-808cm \\M=-808cm](https://img.qammunity.org/2021/formulas/physics/college/fs5bbglorj1920rvgodkswa1u6mh1acdlg.png)
hence from the answer, we can conclude that the magnifying power of the telescope is -808cm