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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

1 Answer

1 vote

Answer:

Part 1)
a=-(1)/(4c^6)

Part 2)
a=-(1)/(4c^(-6))

Explanation:

Part 1) we have


a=2b^(3) ----> equation A


b=-(1)/(2)c^(-2) ----> equation B

substitute equation B in equation A


a=2(-(1)/(2)c^(-2))^(3)

Applying property of exponents


(x^(m))^(n)=x^(m*n)


x^(-m) =(1)/(x^(m))


a=2(-(1)/(2)c^(-2))^(3)=2(-(1)/(2))^3(c^(-2))^(3)=2(-(1)/(8))(c^(-6))=-(1)/(4c^6)

therefore


a=-(1)/(4c^6)

Part 2) we have


a=2b^(3) ----> equation A


b=-(1)/(2c^(-2))=-(c^(2))/(2) ----> equation B

substitute equation B in equation A


a=2(-(c^(2))/(2))^(3)

Applying property of exponents


(x^(m))^(n)=x^(m*n)


x^(-m) =(1)/(x^(m))


a=2(-(c^(2))/(2))^(3)=2(-(c^(6))/(8))

simplify


a=-(c^(6))/(4)

therefore


a=-(1)/(4c^(-6))

User Harshul Pandav
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