Question

A total charge of 6.3 x 10-8 C is placed on a 2.7 cm radius isolated conducting sphere. The surface charge density is: A. 2.55 x 10-4 C/m3 Explain B. 8.64 x 10-5 C/m2 C. 2.75 x 10-5 C/m2 D. 6.88 x 10-6 C/m2 E. 7.43 x 10-7 C/m

Answer 1

`6.88* 10^(-6)\ C/m^2`

Step-by-step explanation:

Q = Total charge =
`6.3* 10^(-8)\ C`

`\rho` = Surface charge density

r = Radius = 2.7 cm

A = Surface area =
`4\pi r^2`

Charge is given by

`Q=A\rho\\\Rightarrow Q=4\pi r^2* \rho\\\Rightarrow \rho=(Q)/(4\pi r^2)\\\Rightarrow \rho=(6.3* 10^(-8))/(4\pi (2.7* 10^(-2))^2)\\\Rightarrow \rho=0.00000687706544224\\\Rightarrow \rho=6.88* 10^(-6)\ C/m^2`

The surface charge density is
`6.88* 10^(-6)\ C/m^2`