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2. How many grams of N2 are required to produce 10.0 grams of NH3? N2 + 3 H2 - 2 NH3

Step 1: Convert 10.0 g of NH3 into moles of NH3.
Step 2: Convert the moles of NH3 calculated in Step 1 into moles of N2.
Step 3: Convert the moles of N2 calculated in Step 2 into grams of N2.
Or... put it all together!

1 Answer

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Answer: N2 + 3 H2 -> 2NH3

Explanation: 28 grams of N2 is used to produce 2*17 grams = 34grams of NH3

1 gram of NH3 is produced by = 28/34 grams of N2
Therefore, 10grams of NH3 is produced by = 28/34*10grams of N2 = 8.235 grams of N2 = 8.235/14 moles of N2 = 0.588 mole of N2
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