6,137 views
27 votes
27 votes
A tree is 18 feet tall and casts a shadow

that is 22 feet long. How far is it from the
end of the shadow to the top of the tree?
Show your work.

User Krishna Mohan
by
2.4k points

2 Answers

13 votes
13 votes

Answer:

28.42 feet

Explanation:

Given

  • Height of tree = 18 feet
  • Length of shadow = 22 feet

To Find

  • Distance b/w top of tree and end of shadow

Solving

  • This resembles a right triangle
  • ⇒ We can use Pythagorean Theorem!
  • ⇒ 18² + 22² = L²
  • ⇒ L² = 324 + 484
  • ⇒ L² = 808
  • ⇒ L = 2√202
  • ⇒ L = 2 x 14.21
  • ⇒ L = 28.42 feet
User Jwinandy
by
2.7k points
10 votes
10 votes

Answer:

28.4 feet

Explanation:

The question can be solved by using Pythagoras Theorem.

Given:-

Height of tree :- 18 feet (Perpendicular)

length of shadow :- 22 feet (Base)

To find:-

Distance of shadow from the end to the top of the tree

Solution:-

We know the Pythagoras theorem,

Which is , H² = P² + B²

So putting the given value , we get

H² = 18²+22²

H² = 324 + 484

H = √ 808 feet

H = 28.4 feet

User Rakib
by
2.9k points