Question

What is the percent by mass of hydrogen in, C9H6O3

Answer 1

Hey there!

Molar mass of ( C₉H₆O₃ ) = 162.14 g/mol

atomic mass H = 1.007 amu

Therefore :

H% = atomic mass H / molar mass ( C₉H₆O₃ ) x 100

H % = ( 1.007 / 162.14 ) x 100 =

H% = 0.00621 x 100 =

H% = 0.621