Question

one night a theater sold 548 movie tickets. an adult’s costs $6.50 an child’s cost $3.50. in all, $2,881 was takin in. how many of each kind of tickets were sold?

Answer 1

• 321 adult tickets
• 227 child tickets

Explanation:

This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...

6.50x +3.50(548-x) = 2881

3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms

3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918

x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3

548-x = 548 -321 = 227 . . . . . .number of child tickets

321 adult tickets and 227 child tickets were sold.