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A pressure gage connected to a tank reads 55 kPa at a location where the atmospheric pressure is 72.1 cmHg. The density of mercury is 13,600 kg/m3 . Calculate the absolute pressure in the tank.

User Dimodi
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Answer:

Step-by-step explanation:

Given

Gauge Pressure of a tank is


P_(gauge)=55\ kPa

at that place atmospheric Pressure is
h=72.1\ cm\ of\ Hg

Density of mercury
\rho _(Hg)=13600\ kg/m^3

Atmospheric Pressure in kPa is given by


P_(atm)=\rho _(Hg)* g* h


P_(atm)=13600* 9.8* 0.721


P_(atm)=96.09\ kPa

and Absolute Pressure is summation of gauge pressure and atmospheric Pressure


P_(abs)=P_(gauge)+P_(atm)


P_(abs)=55+96.09=151.09\ kPa

User Max Langhof
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