Question

8. Given the standard deviation of 16 for a population and a 95% confidence level, find the margin

of error of a sample space containing 60 values.
(1 point)
4.0486
3.3979
0.5227
29.4000

Answer 1

4.0486

Explanation:

The margin of error is calculated using
`E=z_{(\alpha)/(2) }*(\sigma)/(√(n) )`

Where n=60 is the sample size and
`\sigma=16` is the population standard deviation.

The critical value corresponding to 95% confidence interval is
`z_{(\alpha)/(2)}=1.96`

We substitute the values to obtain;

`E=1.96*(16)/(√(60) )`

`E=1.96*2.06559=4.0486`