Question

What is the current in amperes if 1400 Na+ ions flow across a cell membrane in 3.3 μs ? The charge on the sodium is the same as on an electron, but positive.

Answer 1

Current,
`I=6.78* 10^(-11)\ A`

Step-by-step explanation:

In this case, we need to find the current in amperes if 1400 Na+ ions flow across a cell membrane in 3.3 μs.

Charge,
`q=1400* 1.6* 10^(-19)=2.24* 10^(-16)\ C`

Time taken,
`t=3.3\ \mu s=3.3* 10^(-6)\ s`

Let I is the current. It is given by total charge per unit time. It is given by :

`I=(q)/(t)`

`I=(2.24* 10^(-16))/(3.3* 10^(-6))`

`I=6.78* 10^(-11)\ A`

So, the current of
`6.78* 10^(-11)\ A` is flowing across a cell membrane. Hence, this is the required solution.