Answer:
The pH of the solution is 4.28
Step-by-step explanation:
The dissolution reaction as below
CH₃COOH ⇔ CH₃COO⁻ + H⁺
![K_(a) = ([CH_(3)COO^(-)][H^(+)])/([CH_(3)COOH) = 10^(-4.76)](https://img.qammunity.org/2021/formulas/chemistry/college/yix5makykjk0w1u8lsvlm7kbbho7bxm67b.png)
Assume the concentration of the ion, [H⁺] = a,
so [CH₃COO⁻] = a and [CH₃COOH] = 3a
Then use the formula of Ka, we get
Ka = a * a / 3a = 10^-4.76 ⇔ a = 3 x 10^-4.76 = 5.21 x 10^-5
Hence pH = -log(a) = - log(5.21 x 10^-5) = 4.28