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Solve for x in the equation x squared minus 8 x + 41 = 0.

x = negative 4 plus-or-minus StartRoot 37 EndRoot i
x = –4 ± 5i
x = 4 plus-or-minus StartRoot 37 EndRoot i
x = 4 ± 5i

User MetaFight
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2 Answers

6 votes

Answer:

D

Explanation:

trust meh

User Madnx
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6 votes

Answer:

Option 4 - The solution of x is
x=4\pm5i.

Explanation:

Given : Equation
x^2-8x+41=0

To find : Solve for x in the equation ?

Solution :

Solving a quadratic equation
ax^2+bx+c=0 solution is given by,
x=(-b\pm√(b^2-4ac))/(2a)

Here, a=1, b=-8 and c=41


x=(-(-8)\pm√((-8)^2-4(1)(41)))/(2(1))


x=(8\pm√(-100))/(2)


x=(8\pm10i)/(2)


x=4\pm5i

Therefore, the solution of x is
x=4\pm5i.

User Oct
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