Answer:
Mass of the liquid in the tank will be
![1.45* 10^8kg](https://img.qammunity.org/2021/formulas/mathematics/college/3cbi5r0ru6zrkar5j12zzdknzt7wtt64it.png)
Explanation:
We have given volume of tar
![V=3.20* 10^5gallon](https://img.qammunity.org/2021/formulas/mathematics/college/e81m77uccgklj52qbtf6s4ospmdo9fv73t.png)
1 gallon = 3.785 liter
So
![3.20* 10^5gallon=3.20* 10^(5)* 3.785=12.112* 10^5liter](https://img.qammunity.org/2021/formulas/mathematics/college/qvfklkv3lri3qplvmns8k3i00s5d2o2ivz.png)
Specific gravity = 1.2
Density of water
![=1000kg/m^3](https://img.qammunity.org/2021/formulas/mathematics/college/ph0clkxqnyx249bnpqzuyeq62x6wkrwg9g.png)
We know that specific gravity
![=(density\ of\ liquid)/(density\ of\ water)](https://img.qammunity.org/2021/formulas/mathematics/college/p2nl9zx84ap8cy7ex6gbh05hmsn8dyewmt.png)
![1.2=(density\ of\ liquid)/(density\ of\ water)](https://img.qammunity.org/2021/formulas/mathematics/college/bjsn4o30x9hh4w7tpztacw6juov880ep4h.png)
Density of liquid
![=1200kg/m^3](https://img.qammunity.org/2021/formulas/mathematics/college/cdvrv5y2j0vwbkf3gxlhmre81ywx0ki87e.png)
So mass of liquid = volume × density
=
![12.112* 10^5* 1200=1.45* 10^8kg](https://img.qammunity.org/2021/formulas/mathematics/college/s8ucjiec8xouizpgn10d82b38662b83je0.png)
So mass of the liquid in the tank will be
![1.45* 10^8kg](https://img.qammunity.org/2021/formulas/mathematics/college/3cbi5r0ru6zrkar5j12zzdknzt7wtt64it.png)