Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
Explanation:
Given ,
Current balance $320
Minimum balance $100
I could spent =$(320-100) = $220
Let the number of bills be x.
Total amount of x bills = $20x
According to the problem,
20x≤ 220
⇔x ≤
⇔x≤11
Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.