Question

15.2 g of NO2(g) is placed in a sealed 10.0 L flask at room temperature. The total pressure of the system is found to be 0.50 atm. What are the partial pressures of NO2and N2O4are present?

Answer 1

Partial pressure of NO2 = 0.37 atm

Partial pressure of N2O4 = 0.13 atm

Step-by-step explanation:

Number of moles of NO2 = mass/MW = 15.2g/46g/mole = 0.33 mole

Volume of flask = 10L

1 mole of the mixture of gas contains 22.4L of the gas

10L of the gas contains 10/22.4 mole = 0.45 mole

Total mole of gas mixture in the tank = 0.45 mole

Total pressure of the system = 0.5atm

Partial pressure of NO2 = 0.33mole/0.45mole × 0.5atm = 0.37 atm

Partial pressure of N2O4 = 0.5atm - 0.37atm = 0.13atm