160k views
4 votes
Find two consecutive even integers such that the sun of the larger and twice the smaller is 62.

1 Answer

3 votes

Answer:

20 and 22.

Explanation:

Let the consecutive integers be a and b

Then b = a + 2

a is the smaller integer.


\begin{array}{rcl}2a + b & = & 62\\2a + a + 2& = & 62\\3a + 2 & = & 62\\3a & = & 60\\a & = & (60)/(3)\\\\& = & \mathbf{20}\\\end{array}

a = 20

b = 20 + 2 = 22

The two integers, in ascending order, are 20 and 22.

Check:

2(20) + 22 = 62

40 + 22 = 62

62 = 62

OK.

User Jimmt
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories