Question

Suppose a helium-3 nuclide transforms into a helium-4 nuclide by absorbing a proton and emitting a positron. Complete the nuclear chemical equation below so that it describes this nuclear reaction.

Answer 1

The nuclear equation where a helium-3 nuclide transforms into a helium-4 nuclide by absorbing a proton and emitting a positron is written as ³He + ¹H → ⁴He + e⁺. This ensures that mass and charge are conserved in the reaction.

Step-by-step explanation:

To complete the nuclear chemical equation where a helium-3 nuclide (³He) transforms into a helium-4 nuclide (⁴He) by absorbing a proton (¹H) and emitting a positron (e⁺), we must ensure that both mass and charge are conserved in the reaction. In this case, the equation can be represented as:

³He + ¹H → ⁴He + e⁺

The mass number on the left side of the equation is 3 (from helium-3) plus 1 (from the proton), totaling 4, which matches the mass number of helium-4 on the right side of the equation. The atomic number (number of protons) is also conserved through this reaction: 2 (from helium-3) + 1 (from the proton) equals 2 (from helium-4) + 1 (from the emitted positron), with positrons having a positive charge but no atomic number associated.

Answer 2

Answer: The nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.

Step-by-step explanation:

Nuclear reaction are defined as the reactions in which nucleus of an atom is involved.

Positron emission is defined as the emission process in which positron particle is emitted. In this process, a proton gets converted to neutron and an electron neutrino particle.

`_Z^A\textrm{X}\rightarrow _(Z-1)^A\textrm{Y}+_(+1)^0e`

The chemical equation for the reaction of He-3 with a proton follows:

`_2^3\textrm{He}+_1^1\textrm{H}\rightarrow _2^4\textrm{He}+_(+1)^0e`

Hence, the nuclear equation for the conversion of He-3 nuclide to He-4 nuclide is given above.