Answer:
For the first case we are going to assume that the order matters, on this case 6, H is not the same as H,6
The sampling space denoted by S and is given by:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T),(4,T),(5,T),(6,T),
(H,1), (H,2),(H,3), (H,4),(H,5),(H,6),
(T,1), (T,2),(T,3), (T,4), (T,5),(T,6)}
If we consider that (5,H) is equal to (H,5) "order no matter" then we will have just 12 elements in the sampling space:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T) , (4,T), (5,T),(6,T)}
Step-by-step explanation:
By definition the sample space of an experiment "is the set of all possible outcomes or results of that experiment".
For the case described here: "Toss a coin and a six-sided die".
Assuming that we have a six sided die with possible values {1,2,3,4,5,6}
And for the coin we assume that the possible outcomes are {H,T}
For the first case we are going to assume that the order matters, on this case 6, H is not the same as H,6
The sampling space denoted by S and is given by:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T),(4,T),(5,T),(6,T),
(H,1), (H,2),(H,3), (H,4),(H,5),(H,6),
(T,1), (T,2),(T,3), (T,4), (T,5),(T,6)}
If we consider that (5,H) is equal to (H,5) "order no matter" then we will have just 12 elements in the sampling space:
S ={(1,H), (2,H),(3,H),(4,H),(5,H),(6,H),
(1,T), (2,T), (3,T) , (4,T), (5,T),(6,T)}