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The base of a solid is a circle with radius 5. The cross sections of the solid perpendicular to a fixed diameter of the base are squares. If the circle is centered at the origin and the cross sections are perpendicular to the x-axis, find the area A(x) of the cross section at x.

User Pduey
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Final answer:

The cross-sectional area of the square can be found by subtracting the area of the circle from the area of the square. The formula for the area of a square is A = s², where s is the length of one side of the square. The formula for the area of a circle is A = pi * r², where r is the radius of the circle.

Step-by-step explanation:

The cross-sectional area of the square can be found by subtracting the area of the circle from the area of the square. The area of the square is given by the formula A = s², where s is the length of one side of the square. In this case, the side length of the square is equal to the diameter of the circle, which is 2 * radius = 2 * 5 = 10. Therefore, A = 10² = 100 square units. The area of the circle is given by A = pi * r², where r is the radius of the circle. In this case, the radius is 5, so A = pi * 5² = 25pi square units. Therefore, the cross-sectional area of the square at any x is A(x) = 100 - 25pi square units.

User Vedran Maric
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Answer:

Step-by-step explanation:see attachment

The base of a solid is a circle with radius 5. The cross sections of the solid perpendicular-example-1
User BobSki
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