Question

(2x-7)-(4x^2+6x-3)+(x^2+4)

Answer 1

`-3x^2-4x`

Explanation:

Simplify:

`\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)`

`=2x-7-\left(4x^2+6x-3\right)+x^2+4`

Group same factor:

`=-\left(4x^2+6x-3\right)+x^2+2x-7+4`

Add :

`=-\left(4x^2+6x-3\right)+x^2+2x-3`

Apply the distributive law: -(a+b) = -a - b

`-\left(4x^2+6x-3\right)=-4x^2-6x+3`

`=-4x^2-6x+3+x^2+2x-3`

Group same factor:

`=-4x^2+x^2-6x+2x+3-3`

Subtract:

`=-4x^2+x^2-6x+2x`

Add:

`=-3x^2-6x+2x`

Group same factor:

`=-3x^2-4x`

Hence answer =
`-3x^2-4x`

~lenvy~