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How does the graph of g (x) = StartFraction 1 Over x + 4 EndFraction minus 6 compare to the graph of the parent function f (x) = StartFraction 1 Over x EndFraction?

2 Answers

4 votes

Answer:

the graph is shifted 4 units to the left and 6 units down.

I took the test!

User Xiddoc
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5 votes

The transformed equation
$g(x)=(1)/(x+4)-6$ , the graph is shifted 4 units to the left and 6 units down.

Step-by-step explanation:

The parent equation is
$f(x)=(1)/(x)$

The transformed equation is
$g(x)=(1)/(x+4)-6$

By using the function transformation rules, we can see that the parent function
$f(x)=(1)/(x)$ is transformed into the function
$g(x)=(1)/(x+4)-6$

Since, from the function transformation rules, we know that,


$f(x+b)$ shifts the function b units to the left.

Thus, the transformed function is shifted 4 units to the left.

Also, from the function transformation rules, we know that,


$f(x)-b$ shifts the function b units downward.

Thus, the transformed function is shifted 6 units down.

Thus, the transformed equation
$g(x)=(1)/(x+4)-6$ , the graph is shifted 4 units to the left and 6 units down.

User Tejinder
by
3.7k points