Answer:
Number of newspaper distributed = 250
Explanation:
Given:
A graph with linear increment in points.
Lets choose two points from the graph in (x,y) co-ordinate.
From the graph we see that:
For second month there are 200 newspaper distributed by the school.
For the fourth month there are 300 newspaper distribution.
Points in co-ordinate.
and
![(x_1,y_1) = (4,300)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/amy9rkm91kqavteyyb8bi7vzf3s94jkc0u.png)
Using point slope form.
Slope (m) =
(m) =
![(300-200)/(4-2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/iwk9qcpyg4hvn2pig7p3582y4iv5fpkte3.png)
(m) =
![(100)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/31nujomcwtftcqe254wu6l75pe7v5vxl2s.png)
(m) = 50
As the point are linear.
We can say that it will follow slope -intercept form: y=mx+b
Plugging the values,of
in the slope -intercpt form we will find the y-intercept (b) value.
⇒
![b = y-m(x)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vonf5yaqu3n0kebzv906xh0up1uqmrmhtw.png)
⇒
![b=200-50(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5apsceyfv4kgkbei88axmjz41xx0jz7kry.png)
⇒
![b=200-100](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mfrpnhpsfz11v86yzbu4jmcp5b3dj3g03y.png)
⇒
![b=100](https://img.qammunity.org/2021/formulas/mathematics/college/ddns6jkcbitocami6znlhf3c5rwc8ccu14.png)
For third month the 'x' co-ordinate will be 3 and y-cordinate is the number of newspaper distributed.
Plugging the values of x=3, m=50 and b=100
⇒
![y=m(x)+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rpyfkwmuzkzxzcgssfkhr4c06lco5j0rex.png)
⇒
⇒
![y=150+100](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ple6e8eiky947lmuh57fk8eu8e2nwbpqlp.png)
⇒
![y=250](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4vrsqopfrjf71nc355fpo3w5m1mg5rg406.png)
Number of school newspaper distributed in third month = 250 .