Final answer:
The total charge on sphere two, Q2, after being connected to the first sphere by a thin conducting wire, will be the same as the original charge Q, which is 2.9 μC or 2.9 x 10^-6 C.
Step-by-step explanation:
The question pertains to the charge distribution between two connected conductors. When the two conducting spheres are connected by a thin wire, the charges redistribute until the potential is the same on both spheres, regardless of their size. Since the spheres are identical conductors except for their size, and since potential on the surface of a charged spherical conductor is given by V = Q / (4πε0R), where Q is the total charge and R is the radius, for the potential to be equal, the ratio of charges has to be the same as the ratio of their radii. This implies that sphere two also ends up with a total charge of Q, which is 2.9 μC or 2.9 x 10^-6 C after equilibrium.