Question

A rectangle has a length six inches less than twice it’s width. If the perimeter of the rectangle is 54 inches, find the dimensions.

Answer 1

Explanation:

width = W

length = L= 2W-6

P = 2L+2W

84=2(2W-6) + 2W

84= 4W -12 + 2W

84 = 6W -12

84+12 = 6W

96 = 6W

W=16

Solution

W=16

L = 2(16)-6 = 32-6 = 26