Answer:
The new resistance becomes half of the initial resistance.
Step-by-step explanation:
The resistance of a wire is given by :

= resistivity of material
L and A are linear dimension
If the electrical wire is replaced with one having every linear dimension doubled i.e. l' = 2l and r' = 2r
New resistance of wire is given by :




The new resistance becomes half of the initial resistance. Hence, this is the required solution.