Question

Judy (mass 45.0 kg), standing on slippery ice, catches her leaping dog, Atti (mass 10 kg), moving horizontally at 4.0 m/s. Use the conservation of momentum to find the speed of Judy and her dog after the catch. (m/s)

Answer 1

velocity of Judy and dog after collision will be 0.7272 m./sec

Step-by-step explanation:

Mass of the Judy
`m_1=45kg`

As the Judy is standing so initial velocity of Judy
`v_1=0m/sec`

Mass of dog Atti
`m_2=10kg`

Velocity of Atti
`v_2=4m/sec`

We have to fond the velocity of Judy and dog after collision

Now according to conservation of momentum

Momentum before collision is equal to momentum after collision

So
`m_1v_1+m_2v_2=(m_1+m_2)v`

`45* 0+10* 4=(45+10)* v`

v = 0.7272 m/sec

So velocity of Judy and dog after collision will be 0.7272 m./sec