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Let f(x)=x^2-16 and g(x)=x+4. Find f/g and it’s domain

User Jayo
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2 Answers

1 vote

Answer:

Explanation:

f(x)=x^2-16 and g(x)=x+4

f/g = (x²- 16)/(x + 4)

= (x + 4)(x - 4)/(x + 4)

= x - 4

User Bil
by
7.9k points
3 votes

Answer:

f/g=(x+4)

Explanation:

f*g means multiply the functions.

(x^2-16)(x-4)=x^3-4x^2-16x+64.

f/g means divide the functions

(x^2-16)/(x-4), but the numerator is a difference of squares, (x+4)(x-4), and the last cancels the denominator.

f/g=(x+4)

Domains of a composite function are the domains that satisfy both.

f(x) has domain of all reals.

g(x) does too.

Their composite domain is all reals

In the second, the denominator is (x-4).

The function doesn't exist at x=4, regardless of what can be factored. Therefore,

the domain of f/g is all reals except x=4.

User Adem ?Lhan
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