Question

The rate of a certain reaction is given by the following rate law: rate Use this information to answer the question below. At a certain concentration of H2 and NH3, the initial rate of reaction is 4.0 x 105 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled

Answer 1

Initial rate of the reaction when concentration of hydrogen gas is doubled will be
`3.2* 10^6 M/s`.

Step-by-step explanation:

`N_2+3H_2\rightarrow 2NH_3`

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Initial rate of the reaction = R =
`4.0* 10^5 M/s`

`R = k* [N_2][H_2]^3`

`4.0* 10^5 M/s=k* [N_2][H_2]^3`

The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

`[H_2]'=2[H_2]`

`R'=k* [N_2][H_2]'^3=k* [N_2][2H_2]^3`

`R'=8* k* [N_2][H_2]^3`

`R'=8* R=8* 4* 10^5 M/s=3.2* 10^6 M/s`

Initial rate of the reaction when concentration of hydrogen gas is doubled will be
`3.2* 10^6 M/s`.