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Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.50×105 V/m. When the space is filled with dielectric, the electric field is E= 2.30×105 V/m.1.What is the charge density on each surface of the dielectric? (|Sigma i | = ? C/m^2)2.What is the dielectric constant?

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Final answer:

To find the charge density on each surface of the dielectric, use the formula |Sigma i | = epsilon * E. To find the dielectric constant, use the formula epsilon = epsilon_0 * kappa. Rearrange the formula to solve for kappa.

Step-by-step explanation:

To find the charge density on each surface of the dielectric, we can use the formula:

|Sigma i| = epsilon * E

where epsilon is the permittivity of the dielectric and E is the electric field strength. Since the electric field is different when the space is evacuated and when it is filled with a dielectric, we can calculate the charge density for each case using the given electric field values.

To find the dielectric constant, we can use the formula:

epsilon = epsilon_0 * kappa

where epsilon_0 is the permittivity of free space and kappa is the dielectric constant. We can rearrange the formula to solve for kappa.

Using the given values, we can calculate the charge density and dielectric constant:

  • When the space is evacuated: |Sigma i | = epsilon_0 * E = 8.85 x 10-12 * 3.50 x 105
  • When the space is filled with dielectric: |Sigma i | = epsilon_0 * kappa * E = 8.85 x 10-12 * kappa * 2.30 x 105

By solving these equations, we can find the values for charge density on each surface of the dielectric and the dielectric constant.

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