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How many atoms are present in 20.9 g of titanium
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How many atoms are present in 20.9 g of titanium

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Answer:

atoms Ti = 2.193 E23 atoms

Step-by-step explanation:

  • 1 mol ≡ 6.022 E23 atoms
  • mm Ti = 47.867 g/mol

⇒ atoms Ti = (20.9 g Ti)×(mol/47.867 g)×(6.022 E23 atoms/mol)

⇒ atoms Ti = 2.193 E23 atoms

User EpicUsername
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