To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as
![f = f_0 ((v-v_0)/(v))](https://img.qammunity.org/2021/formulas/physics/college/jilzpdrjhrq9k9powf5ehvxh3yr4pj3jim.png)
Here,
= Original frequency
= Velocity of the observer
= Velocity of the speed
Our values are,
![v = 340m/s \rightarrow \text{Speed of sound}](https://img.qammunity.org/2021/formulas/physics/college/xdo4opell5dxq0r8kb26eqtpgz1eg8ix3z.png)
![f = 20kHz \rightarrow \text{Apparent frequency}](https://img.qammunity.org/2021/formulas/physics/college/dnhx6whl7gbala68feft0x6cc4etl5j6i6.png)
![f_0 = 21kHz \rightarrow \text{Original frequency}](https://img.qammunity.org/2021/formulas/physics/college/h6wmh6auba6ky31qgsy5xcjya3e35rpcqc.png)
Using the previous equation,
![f = f_0 ((v-v_0)/(v))](https://img.qammunity.org/2021/formulas/physics/college/jilzpdrjhrq9k9powf5ehvxh3yr4pj3jim.png)
Rearrange to find the velocity of the observer
![v_0 =v (1-(f)/(f_0))](https://img.qammunity.org/2021/formulas/physics/college/e0qcc5uhhd8fv1ck8am3b4ycx1chs1nhbn.png)
Replacing we have that
![v_0= (340m/s)(1-(20kHz)/(21kHz))](https://img.qammunity.org/2021/formulas/physics/college/wm2tt1da1kw33pp5shuin0tpxninlmdr76.png)
![v_0 = 16.19m/s](https://img.qammunity.org/2021/formulas/physics/college/b37jr8fc6r2hcfcb3t256yqz9ndjfh74p6.png)
Therefore the velocity of the observer is 16.2m/s