Question

A 0.683 kg mass moves in SHM at the end of a spring. It takes 1.41 s to move from the position with the spring fully extended to the position with the spring fully compressed. What is the spring constant?

Answer 1

Spring constant of the spring will be equal to 9.255 N /m

Step-by-step explanation:

We have given mass m = 0.683 kg

Time taken to complete one oscillation is given T = 1.41 sec

We have to find the spring constant of the spring

From spring mass system time period is equal to
`T=2\pi \sqrt{(m)/(K)}`, here m is mass and K is spring constant

So
`1.41=2* 3.14\sqrt{(0.683)/(K)}`

`0.2245=\sqrt{(0.683)/(K)}`

Squaring both side

`0.0504=(0.4664)/(K)`

`K=9.255N/m`

So spring constant of the spring will be equal to 9.255 N /m