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A car engine produces an average of 25 kW of power in a period of 10-min during which 1.25 kg of gasoline is consumed. If the heating value of gasoline is 43,000 kJ/kg, the efficiency of this engine during this operation is:

A. 24%B. 28%C. 32%D. 36%

User Prabhuraj
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1 Answer

6 votes

Answer:B

Step-by-step explanation:

Given

Power Produced
P=25\ kW

time
t=10\ min

Gasoline consumed
m=1.25\ kg

Heat capacity of Gasoline
C=43,000\ kJ/kg

Heat Provided by Gasoline
Q_s=m* C


Q_s=1.25* 43000=53,750\ kJ

Energy used in Producing Power is
W=25* 10* 60=15,000\ kJ

Efficiency of an engine is


\eta =(Work)/(Energy\ Supplied)


\eta =(15000)/(53750)=0.2790


\eta =27.90\approx 28\ \%

User Dominik Honnef
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