Answer:
He have 42 oranges and 7 mangoes.
The correct answer is 7 mangoes and 42 oranges.
Explanation:
Given:
Renaldo has six times as many oranges as mangoes. He has 49 pieces of fruit in all. Let r represent the number of oranges and m represent the number of mangoes.
Now to find the number of each fruit Renaldo have.
As, given:
Let
represent the number of oranges and
represent the number of mangoes.
So, as he has six times as many oranges as mangoes.
Thus,
..........( 1 )
Total number of fruits = 49.
According to question:
![m+r=49](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7wo7ih73jz9jbuck4xww94n7qbth595vt8.png)
Substituting the value of
from equation (1) we get:
![m+6m=49](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vzkgl1wtqsy2btusv6cjycbq5d3mpz1xwi.png)
![7m=49](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tcjr8pepxahfgczpz7i3ufdqaouqu7blop.png)
Dividing both sides by 7 we get:
![m=7.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4msixbzumduzav49pwhj67fm4boygr8via.png)
Number of mangoes = 7.
Now, to get the number of oranges we put the value of
in equation (1):
![r=6m](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cwwz1nbljeo8l7130fnzgjmbf2af9y1vuk.png)
![r=6* 7](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b1ezp821c1ijwgetq1fqjo2m2bttdvf9hi.png)
![r=42.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ye7tku2d74ane11q5orjq55cc0y1t508u2.png)
The number of oranges = 42.
Therefore, he have 42 oranges and 7 mangoes.
The correct answer is 7 mangoes and 42 oranges.