Question

You have a 12 sided cube that is numbered from 1 to 12. What is the probability of rolling a 5?

50%
NEXLOUESTION
ASKERUDD
TURN

Answer 1

`p(E)=(1)/(12)`

Step-by-step explanation:

Given:

Side of the cube = 12

event = 5

Solution:

Using probability formula.

`p(E)=(n(E))/(n(S))`

Where:

p(E) = Probability of an event

n(E) = Favourable event

n(S) = Sample space

Sample space of a 12 sided cube that is numbered from 1 to 12.

Sample space = {1,2,3,4,5,6,7,8,9,10,11,12}

`n(S)=12`

Favourable event = {5}

`n(E) = 1`

So the probability of rolling a 5.

`p(E)=(1)/(12)`

Therefore, the probability of rolling a cube for event 5 is
`p(E)=(1)/(12)`