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10) A bowling ball released from rest at the top of a 200.m building falls to the ground under the influ- ence of gravity. Calculate: a) its speed at 5.00 s b) how far it has gone when its speed is 32.
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10) A bowling ball released from rest at the top of a 200.m building falls to the ground under the influ-

ence of gravity. Calculate:
a) its speed at 5.00 s
b) how far it has gone when its speed is 32.0"

User Selindek
by
4.9k points

1 Answer

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Step-by-step explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

a) Find v when t = 5.00 s.

v = at + v₀

v = (9.8 m/s²) (5.00 s) + 0 m/s

v = 49.0 m/s

b) Find Δx when v = 32.0 m/s.

v² = v₀² + 2aΔx

(32.0 m/s)² = (0 m/s)² + 2 (9.8 m/s²) Δx

Δx = 52.2 m

User Shaniqua
by
4.3k points
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