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An online store sells speakers the higher prices sells 170 and the lower priced 90last week the store sold 4 times as many lower prices Spenser combined 3,710

User Amel
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Final answer:

The question relates to mathematical concepts such as statistics, standard deviation, and data analysis applied to real-world scenarios involving pricing and consumer surveys.

Step-by-step explanation:

The subject of this question pertains to Mathematics, specifically related to statistics and calculations involving standard deviation and data analysis. An example provided in the question refers to a scenario where we can calculate the standard deviation of a series of computer prices to determine if there's a larger deviation from the average price than claimed by a manufacturer. Another example involves survey results indicating preferences among men and women for shopping for electronics, which requires statistical interpretation.

User Baumr
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Answer:

The number of lower-priced speaker sold was 28

Step-by-step explanation:

The complete question is

An online store sells two types of speaker. The higher-priced speaker sells for $170 and the lower-priced speaker sells for $90. Last week the store sold four times as many lower-priced speaker as higher-priced speaker. Combined sales totaled $3,710. How many lower-priced speaker did it sell?

Let

x ----> the number of higher-priced speaker sold

y ----> the number of lower-priced speaker sold

we know that

Last week the store sold four times as many lower-priced speaker as higher-priced speaker

so


y=4x ----> equation A

Combined sales totaled $3,710

so


170x+90y=3,710 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

Using a graphing tool

The solution is the point (7,28)

see the attached figure

therefore

The number of lower-priced speaker sold was 28 and the number of higher-priced speaker sold was 7

An online store sells speakers the higher prices sells 170 and the lower priced 90last-example-1
User Philibert Perusse
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