Answer:
The total cost is $112.
The cost was found using this expression: 16(3) + 8(8)
Explanation:
To find the cost of any ticket, you would multiply the ticket cost by the number of tickets.
For adult tickets, you would multiply 16 by the number of tickets. This can be represented algebraically.
let 'a' be the number of adult tickets
16a
For children's tickets, you would multiply 8 by the number of tickets. Algebraically, it is:
let 'c' be the number of children's tickets
8c
If you wanted to buy both ticket types, you would add each product. The total cost of tickets is:
16a + 8c This is the general expression
If we want to buy 3 adult tickets and 8 children's tickets, substitute a = 3 and c = 8 into 16a + 8c.
16a + 8c
= 16(3) + 8(8) Multiply each pairs of factors
= 48 + 64 Add
= 112 Total cost
Write in the dollar sign $.
Therefore the total cost of three adult tickets and eight children's tickets is $112.