Answer:
![x^2+2x+4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s5a7ymavueu8xv5bfm21ipq3kktbpt2ucn.png)
Explanation:
The expression given in the exercise is:
![(x^3-8)/(x-2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ws3z45x89invt3ydwsbcyibcbpaimvyfr2.png)
If you descompose the number 8 into its prime factors, you get that:
![8=2*2*2=2^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/21m0bh53jbwky56dr20oc8rzgckp05yaek.png)
Therefore, you can rewrite the numerator of the expression as following:
![=((x^3-2^3))/((x-2))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3d9hn3tl79hmbv4ji929hyxe7701xtpwia.png)
For this exercise you need to remember that for a Difference of cubes:
![a^3-b^3=(a-b)(a^2+ab+b^2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ibmich66ohtcraw2xplo7y4lbwdhk6ctbr.png)
Then, applying this, you get:
![=((x-2)(x^2+2x+2^2))/((x-2))=((x-2)(x^2+2x+4))/((x-2))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/v65ox93xlvy039vrckm3snyvr9tqen7jhc.png)
Now, it is necessary to remember the following:
![(a)/(a)=1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ho0rxesogzuuu5jd00ol9new7oulfuh8s1.png)
Knowing the above, you can say that:
![((x-2))/((x-2))=1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kvvy4tsnkb5e63xyw4f0fdja60iakm6gzd.png)
Therefore applying this, you get that the simplified expression is:
![=x^2+2x+4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ni4im1t77cz2bn1c7894wp7djz6x0s10ao.png)