Question

A line has a slope of 10 and includes the points (-3, -4) and (-2, r). What is the value of r?

Answer 1

6 = r

Step-by-step explanation:

Slope =
`(y2 - y1)/(x2 - x1)`

`(-3,-4)....x1 = -3` and
`y1 = -4`

`(-2,r)....x2 = -2` and
`y2 = r`

Slope =
`10`

Now substitute.

`10 = (r - (-4) / (-2 - (-3)\\10 = (r + 4) / (-2 + 3)\\10 = (r + 4) / 1`

Multiply both sides by 1, eliminating the 1 on the right

`10 * 1 = r + 4\\10 = r + 4\\10 - 4 = r\\6 = r`

Answer 2

Step-by-step explanation:

slope = (y2 - y1) / (x2 - x1)

(-3,-4)....x1 = -3 and y1 = -4

(-2,r)....x2 = -2 and y2 = r

slope = 10

now sub

10 = (r - (-4) / (-2 - (-3)

10 = (r + 4) / (-2 + 3)

10 = (r + 4) / 1.....multiply both sides by 1, eliminating the 1 on the right

10 * 1 = r + 4

10 = r + 4

10 - 4 = r

6 = r <======