Question

Find an equation for the line parallel to 4y-36x=16 and goes through the point (-4,5). Answer in form y=Mx+b

Answer 1

`y=9x+41`

Explanation:

Given line equation as:

`4y-36x=16`

Passing through the point (-4,5)

Solution:

First we convert given line equation in standard form.

`4y-36x=16`

`4y=36x+16`

Divided by 4 both side of the equation.

`y = 9x+4`

So, slope of the above line by comparing with
`y = mx+b`

m = 9

Using point slope formula.

`y - y_(1)=m(x-x_(1))`

We know that the slope of the parallel is same.

Plug in m = 9 and Point
`P(x_(1), y_(1)) = P(-4, 5)` in above formula.

`y - 5=9(x-(-4))`

`y - 5=9(x+4)`

`y - 5=9x+36`

`y=9x+36+5`

`y=9x+41`

Therefore, The equation of the parallel line is
`y=9x+41`