Question

EDU 2020

log6^15= 1.511
Write log146−log14 3/2 as a single logarithm
ANSWER A
Expand logw xz .
ANSWER C

Answer 1

For Edge and since this was already answered

Answer 2

`\log_615=1.511`

`\log_(14)6-\log_(14)(3)/(2)=\log_(14)4`

`\log_w (x)/(z)=\log_wx-\log_w z`

Explanation:

By quotient property :

`\log_xa-\log_xb=\log_x(a)/(b)`

Given:

`\log_630\approx 1.898` and
`\log_62\approx 0.387`

To find
`\log_615`

Solution:

Applying quotient property:

`\log_630-\log_62=\log_6(30)/(2)=\log_615`

`\log_615=\log_630-\log_62`

`\log_615=1.898-0.387`

`\log_615=1.511`

To write
`\log_(14)6-\log_(14)(3)/(2)` as a single logarithm.

Solution:

Applying quotient property:

`\log_(14)6-\log_(14)(3)/(2)=\log_(14)(6)/((3)/(2))`

`\log_(14)6-\log_(14)(3)/(2)=\log_(14)(6* (2)/(3))`

`\log_(14)6-\log_(14)(3)/(2)=\log_(14)4`

To expand
`\log_w (x)/(z)`

Solution:

Applying quotient property:

`\log_w (x)/(z)=\log_wx-\log_w z`